At the Equator, the distance between meridians of longitude is 60 n.m. (or 60.113 to be precise). However, as we move north or south equator, we find that the distance between them decreases as they converge towards the poles. So how do we calculate the distance between meridians of longitude along a particular parallel of latitude?
Let AB be an arc of no of longitude measured along a parallel of latitude.
Let Q be the centre of the plane of the small circle which is the parallel of latitude.
Let O be the centre of the plane of the Equator.
Then angle A Q B = angle D O C
Using the formula C = 2πr, we can deduce that the circumference of the Equator equals 2π.CO (since CO represents the radius of the Earth in the diagram).
Therefore it follows that 1o of longitude corresponds to an arc of
2π.CO / 360
⇒ CD = 2πn.CO /360 ⇒ CO = 360.CD / 2πn
by similar argument:
AB = 2πn.BQ / 360 ⇒ BQ = 360.AB / 2πn
angle BOC represents the latitude,
Therefore angle QOB = 90o – Lat.
and angle QBO = Lat. (alternate angles).
angle OQB = 90o (since the plane of QAB is at right-angles to the polar axis).
⇒ QBO is a right angle triangle
Therefore Sin (QOB) = BQ/BO
⇒ Sin (90o – Lat.) = BQ / BO
Also CO = BO = r (since r = Earth’s radius) ⇒Sin (90o-Lat.) = BQ /CO
(since angle QBO = Lat.)
Also Cos Lat. = BQ/CO (since CO = BO)
⇒ BQ = CO Cos Lat.
⇒ 360.AB /2πn = 360.CD Cos Lat /2πn
⇒ arc AB = arc CD Cos Lat.
⇒ Distance AB = CD (difference in long) x Cos Lat. (since 1 nautical mile along the Equator equals 1 minute of arc).
Therefore, to calculate the difference in distance along a parallel of latitude (Ddist) corresponding to a difference in longitude (Dlong) we have the formula:
Ddist = Dlong x Cos Lat.
⇒ Dlong = Ddist /Cos Lat.
Note. Since the secant is the inverse of the cosine, the formula for Dlong can be simplified to: Dlong = Ddist x Sec Lat.